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http://beldmit.livejournal.com/ (
beldmit.livejournal.com
) wrote
in
edhelwen
2017-04-24 11:02 am (UTC)
no subject
Вторая печатает p страниц в час, первая q. Нужно найти X/q.
2p+3q=X
X/p - X/q = 4
Исключаем X, q/p = t, получаем 3t
2
-5t-2=0. Два корня, отрицательный не подходит. t=2.
X/(q/2) - X/q = 4.
X/q = 4.
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no subject
2p+3q=X
X/p - X/q = 4
Исключаем X, q/p = t, получаем 3t2-5t-2=0. Два корня, отрицательный не подходит. t=2.
X/(q/2) - X/q = 4.
X/q = 4.